কোনো বস্তু টেবিলের উপর দিয়ে 1m/sec বেগে গড়াতে গড়াতে মাটিতে পড়ে।বস্তুটি যদি টেবিল থেকে 0.5m দূরে মাটিতে আঘাত করে তবে টেবিলের উচ্চতা কত হবে?
Created: 2 years ago |
Updated: 8 months ago
best des
Given:
Initial horizontal velocity (u) = 1 m/s
Horizontal distance (x) = 0.5 m (distance from the table)
Vertical acceleration (g) = 9.8 m/s²
Vertical displacement (y) = height of the table
We know,
x = ut
From this equation,
t = x / u
Now,
y = ut + 0.5 * a * t²
Substitute the value of t from the horizontal motion equation: t = x / u
y = (0) * (x / u) + 0.5 * g * (x / u)²
y = 0.5 * g * (x / u)²
y = 0.5 * (9.8 m/s²) * (0.5 m / 1 m/s)²
Calculate: y = 0.5 * 9.8 * 0.25 y = 1.225 m
So, the height of the table is approximately 1.225 meters.
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